# Line slope calculator 9x+8y=80

**Straight line given by points A[0; 10] and B[8; 1]**

## Calculation:

**Slope-intercept form of line:**y = -1.125x+10

**Canonical form of the line equation:**9x+8y-80 = 0

**Parametric form of the line equation:**

x = 8t

y = -9t+10 ; t ∈ R

**Slope:**m = -1.125

**Slope angle of line: φ =**-48°21'59″ = -0.8442 rad

**X intercept:**x

_{0}= 8.8889

**Y intercept:**y

_{0}= q = 10

**Distance line from the origin:**d

_{0}= 6.6436

**The length of the segment AB: |AB| =**12.0416

**Vector: AB =**(8; -9)

**Normal vector: n =**(9; 8)

**Midpoint of the segment AB: M =**[4; 5.5]

**Perpendicular Bisector equation:**8x-9y+17.5 = 0

**Vector OA = (0; 10) ; |OA| = 10**

**Vector OB = (8; 1) ; |OB| = 8.0623**

**Scalar product OA .OB = 10**

**Angle ∠ AOB = 82°52'30″ = 1.4464 rad**